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V-Curves and Inverted V-Curves

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 V-Curves and Inverted V-Curves of Synchronous Motor

A synchronous motor is a double-excited machine, its armature winding is energized from an a.c source and its field winding from d.c source.Synchronous motor operates at unity power factor when field current is enough to set up the air-gap flux, as demanded by constant applied voltage.This field current, which causes unity power factor operation of the synchronous motor, is called normal excitation or normal field current.

If the the motor is under excited i.e, current is less than normal excitation,there will be some deficiency in flux to compensate that winding draws a magnetizing current from the a.c source and as a result of it, the motor operates at a lagging power factor.In other case, in over excited i.e, field current more than normal excitation machine operates at leading power factor.In the below figure you can observe leading and lagging variations.
In synchronous motors  performance characteristics obtained by v-curves and inverted v-curves. Synchronous machines have parabolic type characteristics.If excitation is varied from very low (under excitation) to very high (over excitation) value, then current Ia decreases, becomes minimum at unity p.f. and then again increases.But initial lagging current becomes unity and then becomes leading in nature.V-curves and inverted V-curves are used to analyze motor efficiency with no-load and with load.

What are V and inverted V curves ?

  • V-curve is a graph between Ia Vs If.
  • Inverted V curve are drawn between cosΦ Vs If.
In the above two cases If (field current) taken on x-axis.We can control the field excitation of synchronous motor by increasing/decreasing the field current.

Experiment to Obtain V-Curves and Inverted V-Curves 

If graph of armature current drawn by the motor (Ia) against field current (If) is plotted, then its shape looks like alphabet V. If the power factor (cos Φ) is plotted against field current (If), then the shape of the graph looks like an inverted V.
v and inverted v curves of synchronous motor circuit diagram
  • Connect stator of motor to 3 phase supply as shown in the above figure through watt meters and ammeter.
  • In this experiment two watt meter method is used to measure input power of motor.Ammeter reads the line current which is same as armature (stator) current. Voltmeter is reads line voltage.
  • A rheostat in a potential divider arrangement is used in the field circuit to control the excitation.By changing its value note down the voltage,armature current,watt meter readings(W1&W2) in a table like below.

 Now IL = Ia, per phase value can be determined, from the stator winding connections. 
       IL = Iaph for stator connection
       IL/√3 = Iaph for delta connection
       The power factor can be obtained as
From above values make a final table like this,


The graph can be plotted from this result table.
1) Ia Vs If  → V-curve
2) cosΦ Vs If  → Inverted V-curve
This is the entire procedure can be repeated for various load conditions to obtain of V-curves and Inverted V-curves of any synchronous motor.

Tags: v and inverted v curves of synchronous motor wikipedia,v and inverted v curves of 3 phase synchronous motor


Differences Between Synchronous and Induction Motor

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Differences Between Synchronous and Induction Motor

We have two major types of AC motors.They are synchronous and induction motor,synchronous motor runs at synchronous speed where induction motor runs at less than synchronous speed.In this article we are going to discuss on comparisons between synchronous and induction motor. There are so many differences between synchronous motor and induction motor like excitation,speed control.etc.Most important points are listed below.

Synchronous MotorInduction Motor
Construction is complicated.Construction is simpler , particularly in
case of cage rotor.
Not self starting.(why read here)Self starting.
Separate DC source is required for rotor
excitation.
Rotor gets excited by the induced e.m.f
so separate source is not necessary.
The speed is always synchronous irrespective
of the load.
The speed is always less than synchronous
but never synchronous.
Speed control is not possible.Speed control is possible though difficult.
As load increases, load angle increases,keeping
speed constant at synchronous.
As load increases , the speed keeps on
decreasing.
By changing excitation , the motor p.f can be
changed from lagging and leading.
It always operates at lagging p.f and p.f
control is not possible.
It can be used as synchronous condenser for p.f
improvement.
It can not be used as synchronous condenser.
Motor is sensitive to sudden load changes and
hunting results.
Phenomenon of hunting is absent.
Motor is costly and requires frequent maintenance.Motor is cheap, especially cage rotors and
maintenance free.

Read Here: Differences B/W Induction Motor & Transformer
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Blocked Rotor Test On Induction Motor

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Blocked Rotor Test On Induction Motor

This test is also called as Locked Rotor test or short circuit test.In the previous articles we had discussions on construction of induction motor,working of induction motor.We know induction motor is functionally similar to transformer.Like short circuit test on transformer blocked rotor test on induction motor is conducted.
Quick Point: Blocked rotor test on induction motor is to find out stator copper loss, rotor copper loss without friction and windage losses. 
In this test, the rotor is blocked by a belt-pulley mechanism,so it is not allowed to rotate.So rotor speed will be zero (N= 0).So slip (s) =1 and RL' = R2' (1-s)/s is zero.If the induction motor whichever is using for this test is slip ring induction motor then the winding are short circuited at the slip rings. 

Procedure of  Blocked Rotor Test of Induction Motor



1.First block the rotor of induction motor by pulley-belt mechanism.
2.Apply 10 to 15 % of rated voltage to stator of induction motor.(Because if we apply even more than 30% rated voltage rotor will be short circuited.)
3.Now, slowly increase the voltage in the stator winding so that current reaches to its rated value. At this point, note down the readings of the voltmeter, wattmeter and ammeter to know the values of voltage, power and current.
4.Now the applied voltage Vsc, the input power Wsc and a short circuit current Isc are measured.

As RL' = 0, the equivalent circuit is exactly similar to that of a transformer and hence the calculations are similar to that of short circuit test on a transformer.
                     Vsc = Short circuit reduced voltage (line value)
                     Isc = Short circuit current (line value)
                     Wsc = Short circuit input power
       Now      Wsc = √3Vsc Isc cosΦsc ----------- Line values
cosΦsc=Wsc/√3Vsc Isc ( This gives us short circuit power factor of a motor.)
        Now the equivalent circuit is as shown in above figure.
Wsc=3(Isc)²R1e
        where Isc = Per phase value
R1e = Wsc/3(Isc)²
This is equivalent resistance referred to stator.
                       Z1e = Vsc (per phase)/ Isc (per phase) = Equivalent impedance referred to stator.

X1e = 1e-1e  =  equivalent reactance reffered to stator.
              
During this test, the stator carries rated current hence the stator copper loss is also dominant. Similarly the rotor also carries short circuit current to produce dominant rotor copper loss. As the voltage is reduced, the iron loss which is proportional to voltage is negligibly small. The motor is at standstill hence mechanical loss i.e. friction and windage loss is absent. Hence we can write,

Wsc = Stator copper loss + Rotor copper loss

But it is necessary to obtain short circuit current when normal voltage is applied to the motor. This is practically not possible. But the reduced voltage test results can be used to find current ISN which is short circuit current if normal voltage is applied.
If             VL = Normal rated voltage (line value)
                Vsc = Reduced short circuit voltage (line voltage)
then  ISN = (VL * ISC) /Vsc
where       Isc = Short circuit current at reduced voltage
Thus,        ISN = Short circuit current at normal voltage
Now power input is proportional to square of the current.
So   WSN = Short circuit input power at normal voltage
This cab be obtained as,
But at normal voltage core loss can not be negligible hence,
WSN = Wsc (ISN / ISC
       WSN = Core loss + Stator and rotor copper loss

EMF Equation Of Alternator / 3 Phase AC Generator EMF Equation

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EMF Equation of an Alternator

We know Synchronous Machines generates E.M.F.the amount of EMF generated can be calculated using below simple derivation.

Consider following
Φ= flux per pole in wb
P = Number of poles
Ns = Synchronous speed in rpm
f = frequency of induced emf in Hz
Z = total number of stator conductors
Zph = conductors per phase connected in series
Tph = Number of turns per phase
Assuming concentrated winding, considering one conductor placed in a slot
According to Faraday's Law electromagnetic induction,
The average value of emf induced per conductor in one revolution 
eavg = dΦ /dt
eavg = Change of Flux in one revolution/ Time taken for one revolution

Change of Flux in one revolution = p x Φ
Time taken for one revolution = 60/Ns seconds.
Hence eavg = (p x  Φ  ) / ( 60/Ns) = p x   Φ x Ns / 60
We know f = PNs /120
hence PNs /60 = 2f
Hence eavg = 2   Φ f volts
Hence average emf per turn = 2 x 2Φ f volts = 4Φf volts
If there are Tph, number of turns per phase connected in series, then average emf induced in Tph turns is
Eph,avg = Tph x eavg = 4 f   Φ Tph volts

Hence RMS value of emf induced E = 1.11 x Eph, avg
= 1.11 x 4  Φ f Tph volts
= 4.44 f  Φ Tph volts

Eph,avg= 4.44 f  Φ Tph volts

This is the general emf equation for the machine having concentrated and full pitched winding.In practice, alternators will have short pitched winding and hence coil span will not be  180o(degrees), but on or two slots short than the full pitch.

***If we assume effect of 
Kd= Distribution factor
Kc or KP = Cos α/2

Eph,avg= 4.44Kc  Kd f  Φ Tph volts
This is the actual available voltage equation of an alternator per phase.If alternator or AC Generator is Star Connected as usually the case, then the Line Voltage is √3 times the phase voltage.

Tags:derive the emf equation of an alternator,emf equation of synchronous machine,emf equation of induction motor,emf equation of synchronous generator,emf equation of alternator pdf,emf equation of an alternator wikipedia

What Are The Harmonics In Synchronous Machines

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Harmonics Harmonics In Synchronous Machines

Harmonics: When the uniformly sinusoidally distributed air gap flux is cut by either the stationary or rotating armature sinusoidal emf is induced in the alternator. Hence the nature of the waveform of induced emf and current is sinusoidal. But when the alternator is loaded waveform will not continue to be sinusoidal or becomes non-sinusoidal. Such non-sinusoidal wave form is called complex wave form.

By using Fourier series representation it is possible to represent complex non-sinusoidal waveform in terms of series of sinusoidal components called harmonics, whose frequencies are integral multiples of fundamental wave. The fundamental wave form is one which is having the frequency same as that of complex wave.The waveform, which is of the frequency twice that of the fundamental is called second harmonic. The one which is having the frequency three times that of the fundamental is called third harmonic and soon. These harmonic components can be represented as follows.

Fundamental: e1 = Em1 Sin ( t ± θ1)
2nd Hermonic e2 = Em2 Sin (2 t ± θ2)
3rd Harmonic e3 = Em3 Sin (3 t ± θ3)
5th Harmonic e5 = Em5 Sin (5 t ± θ5) etc.
In case of alternators as the field system and the stator coils are symmetrical the induced emf will also be symmetrical and hence the generated emf in an alternator will not contain any even harmonics.

Slot Harmonics: As the armature or stator of an alternator is slotted, some harmonics are induced into the emf which is called slot harmonics. The presence of slot in the stator makes the air gap reluctance at the surface of the stator non uniform. Since in case of alternators the poles are moving or there is a relative motion between the stator and rotor, the slots and the teeth alternately occupy any point in the air gap. Due to this the reluctance or the air gap will be continuously varying. Due to this variation of reluctance ripples will be formed in the air gap between the rotor and stator slots and teeth. This ripple formed in the air gap will induce ripple emf called slot harmonics.

Minimization Techniques of Harmonics: To minimize the harmonics in the induced waveforms following methods are employed:
1. Distribution of stator winding.
2. Short Chording
3. Fractional slot winding
4. Skewing
5. Larger air gap length.

Effect of Harmonics on induced emf:

The harmonics will affect both pitch factor and distribution factor and hence the induced emf. In a well designed alternator the air gap flux density distribution will be symmetrical and hence can be represented in Fourier series as follows.

The RMS value of the resultant voltage induced can be given as

Eph2 =  [(E1)2+ ....+ …………… (En)2]

**(A)2 Means A Square 

Effect of Harmonics of pitch and distribution Factor:

The pitch factor is given by Kp = cos /2, where is the chording angle.
For any harmonic say nthharmonic the pitch factor is given by Kpn = cos n α/2
The distribution factor is given by Kd = (sin mβ /2) / (m sin β/2)

For any harmonic say nth harmonic the distribution factor is given by 
Kdn = (sin mn β/2)/(m sin nβ/2)

This is the detailed info about Harmonics In Synchronous Machines,Minimization Methods of Harmonics.Effect of Harmonics on induced emf.

Difference Between Shell And Core Type Transformers - Types of Transformers

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In our previous articles we have discusses about differences between lap,wave winding.In this tutorial we are sharing major differences between core type transformer and shell type transformer. There are two major types of transformers based on construction.
They are ,
1.Core Type Transformers
2.Shell Type Transformers


In this tutorial comparisons between shell type and core type transformers are discussed.

Types of Transformers

Difference Between Shell And Core Type Transformers 


Core Type TransformersShell Type Transformers
1. In core type transformer winding is placed on
two core limbs.
1. In shell type transformer winding is placed on mid arm
of the core.It is installed on mid-limb of the core.
Other limbs will be used as mechanical supporting
2. Core type transformers have only one magnetic flux path.2. Shell type transformers have two magnetic flux path.
3. It has better cooling since more surface is exposed to
atmosphere.
3. Cooling is not effective in shell type when compared
to core type transformer.
4. It is very useful when we need large size low voltage.4. It is very useful when we need small size high voltage.
5. In core type transformer output is less. Because of losses.
So efficiency will be less than shell type transformer.
5. In core type transformer output is high. Because of
less losses.So efficiency will be more.
6. The winding is surrounded considerable part of core.6. Core is surrounded considerable part of winding of
transformer.
7. It has less mechanical protection to coil.7. It has better mechanical protection to coil.
8. Core has two limbs.8. Core has three limbs.
9. This transformer is easy to repair,Easy to maintain.9. This transformer is not easy to repair.We need a
skilled technician to maintain this type of transformer.
10. In this type transformer concentric cylindrical
winding are used
10. In this type transformer sandwiched winding are used.


Tags: 
1.difference between core type and shell type transformer pdf
2.difference between core type and shell type transformer ppt
3.difference b/w core type and shell type transformer
4.Types of Transformers

Condition for Maximum Efficiency of DC Machine

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We have discussed about construction & working of DC machine. In this article  condition for maximum efficiency in DC machine will be derived. 

Condition for Maximum Efficiency in DC Machine

In this DC generator is taken as reference to find out maximum efficiency .The DC generator efficiency is perpetual but varies with load. Think through a shunt generator supplying a load current IL at a terminal voltage V.


Then Generator output  =  VIL
Generator input  =  Output + Losses

=  VI+ Variable losses + Constant losses
=  VI+ I2R+ Wc
=  VIL + (IL + Ish2)Ra + Wc  ( ∵  Ia = IL + Ish)

The shunt field current Ish is generally small as compared to Iand, therefore, can be neglected.
Generator input   =  VIL + I2a Ra + Wc

Now                Efficiency   η  =  output / Input

=  VI/ (VIL + I2a Ra + Wc
=  1 / {1+[(ILRa/V)+(Wc/VIL)]}

The efficiency is always maximum when the denominator of above equation  is minimum i.e.,
                                              d/dI{( ILRa/V) + (Wc+VI2L)} =0
                                                        Or
                                             (Ra/V) – (Wc/ VI2L) =0
                                                        Or
                                              Ra/V = Wc/VI2L
                                                       Or
                                               I2LRa = Wc

I.e. Variable loss = Constant loss (IL ≈ Ia)
The load current corresponding to maximum efficiency is given by;
                                             
I= √ Wc/Ra

Therefore, the efficiency of a DC generator will be maximum when the variable loss is equal to the constant loss.

Barkhausen Criterion of Oscillators

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Barkhausen Criterion of Oscillators

Consider a basic inverting amplifier with an Open loop gain A.The feedback network attenuation factor B is less than unity. As basic amplifier is inverting. it produces a phase shift of 180° between input and output as shown in the below figure.

Now the input Vi applied to the amplifier is to be derived from its output Vo using feedback network.

But the feedback must be positive Le. the voltage derived from output using feedback network must be in phase with V‘. Thus the feedback network must introduce a phase shift of 180° while feeding back the voltage from output to input. This more: positive feedback.


Consider a fictitious voltage Vi applied at the input of the amplifier. Hence we get,

Vo=AVi    -----------------(1)

The feedback factor β decides the feedback to be given to input,

Vf=βVo    -----------------(2)

Substituting equation (1) into equation (2) we get,

Vf=βAVi    -----------------(3)

For the oscillator, we want that feedback should drive the amplifier and hence V, must act as Vi. From equation (3) we can write that, V, is sufficient to act as V, when.

Aβ | = 1

And the phase of Vf is same as Vi i.e. feedback network should introduce 180°phase shift in addition to 180° phase shift introduced by inverting amplifier. This ensures positive feedback. So total phase shift around a loop is 360°.  In this condition, Vf drives the circuit and without external input circuit works as an oscillator.  The two conditions discussed above, required to work the circuit as an oscillator are called Barkhamen Criterion for Oscillation.


The Barkhausen Criterion states that
1.The total phase shift around a loop,as the signal proceeds from input through amplifier, feedback network back to input again. completing a loop, is precisely 0° or 360°.
2. The magnitude of the product of the open loop gain of the amplifier (A) and Magnitude of the feedback factor-β is unity Le. I Aβ I =1.



In reality, no input signal is needed to start the oscillation. In practice, Aβ is made greater than 1 to start the oscillations and then circuit adjusts it self to get Aβ=1 finally resulting into self sustained oscillations. Let us see the effect of the magnitude of the product Aβ on the nature of the oscillations.

Condition I Aβ I > 1

When the total phase shift around a loop is  or 360° and l Aβ|] > 1,then the  output oscillates but the oscillations are of growing type. The amplitude of oscillations goes on increasing as shown in the below figure.

Condition I Aβ I = 1

As stated  by Barkhausen Criterion, when total phase shift around a loop is 0°or 360° ensuring positive feedback and I Aβ I = 1 then the oscillations are with constant frequency and amplitude called sustained oscillations.
Condition I Aβ I < 1

When total phase shift around a output loop is 0°or 360 °but I Aβ I< 1 then the oscillations are of decaying type i.e. such oscillation amplitude decreases  exponentially and the oscillations finally cease. Thus circuit works as an amplifier without oscillations.So to start the oscillations without input I Aβ I is kept higher than unity and then circuit adjusts itself to get | Aβ | = l to result sustained oscillations.



[ PDF ] Analog Electronics Book Bakshi and Godse Free Download Pdf

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Analog Electronics Book  Bakshi and Godse Free Download Pdf

We at ElectricalEdition.Com Always try to help electrical & electronics engineering students by providing articles,PDF books for free download,PPTs,Email Answering etc.As a part of this we are sharing Pdf Book: Analog Electronics Book  Bakshi and Godse For Free Download.


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Long transmission lines,Analysis With Rigorous Method

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Long transmission lines,Analysis By Rigorous method

What are called as Long transmission lines?

Answer: When the length of an overhead transmission line is more than 150 km and line voltage is very high (> 100 kV), it is considered as a long transmission line. For the treatment of such a line, the line constants are considered uniformly distributed over the whole length of the line and rigorous methods are employed for solution.

Long transmission lines:

It is well known that line constants of the transmission line are uniformly distributed over the entire length of the line. However, reasonable accuracy can be obtained in line calculations for short and medium lines by considering these constants as lumped. If such an assumption of lumped constants is applied to long transmission lines (having length excess of about 150 km), it is found that serious errors are introduced in the performance calculations. Therefore, in order to obtain fair degree of accuracy in the performance calculations of long lines, the line constants are considered as uniformly distributed throughout the length of the line. Rigorous mathematical treatment is required for the solution of such lines.



Above shows the equivalent circuit of a 3-phase long transmission line on a phase-neutral basis. The whole line length is divided into n sections, each section having line constants 1/n th of those for the whole line. The following points may by noted :

(i) The line constants are uniformly distributed over the entire length of line as is actually the case.
(ii) The resistance and inductive reactance are the series elements.
(iii) The leakage susceptance (B) and leakage conductance (G) are shunt elements. The leakage susceptance is due to the fact that capacitance exists between line and neutral. The leakage conductance takes into account the energy losses occurring through leakage over the insulators or due to corona effect between conductors.

Admittance =√G ²+B²

(iv) The leakage current through shunt admittance is maximum at the sending end of the line and decreases continuously as the receiving end of the circuit is approached at which point its value is zero.

Analysis of  Long Transmission Line (Rigorous method)

Below shows one phase and neutral connection of a 3-phase line with impedance and shunt admittance of the line uniformly distributed.


Consider a small element in the line of length dx situated at a distance x from the receiving end.
Let z = series impedance of the line per unit length
y = shunt admittance of the line per unit length
V = voltage at the end of element towards receiving end
V + dV = voltage at the end of element towards sending end
I + dI = current entering the element dx
I = current leaving the element dx
Then for the small element dx,
z dx = series impedance
y dx = shunt admittance
Obviously, dV = I z dx
or dV/dx = I z  ...(i)
Now, the current entering the element is I + dI whereas the current leaving the element is I. The difference in the currents flows through shunt admittance of the element i.e., 
dI = Current through shunt admittance of element = V y dx
dI/dx= V y  ...(ii)
Differentiating eq. (i) w.r.t. x, we get,










Back EMF | Back EMF Significance in DC Motor

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Back EMF | Back EMF Significance in DC Motor

What is Back EMF in DC Motor?


We know whenever conductor cuts the magnetic field,e.m.f will induce in conductor.This also applies for conductors in armature too.When the armature of a d.c. motor rotates under the influence of the driving torque, the armature conductors move through the magnetic field and hence e.m.f. is induced in them as in a generator. The induced e.m.f. acts in opposite direction to the applied voltage  V (Lenz’s law) and in known as back e.m.f or counter e.m.f. denoted with  Eb. 

The back emf  Eb(= PΦZN/60 A) is always less than the applied voltage V, although this difference is small when the motor is running under normal conditions.

Back EMF in DC Motor Circuit Diagram



Significance of Back EMF In DC Motor:


It is seen in the generating action, that when a conductor cuts the lines of flux, emf. gets induced in the conductor. The question is obvious that in a dc. motor, after a motoring action, armature starts rotating and armature conductors cut the min flux.So is there a generating action exiting in a motor ? The answer to this question is 'Yes'

After a motoring action, there exists a generating action.There is an induced e.m.f in the rotating armature conductors according to Faraday's law of electromagnetic induction. This induced e.m.f. in the armature always acts in the opposite direction of the supply voltage. This is according to the Lenz’s law which states that the direction of the induced e.m.f. is always so as to oppose the cause producing it. In a dc. motor, electrical input i.e. the supply voltage is the cause and hence this induced e.m.f. opposes the supply voltage. This e.m.f tries to set up a current through the armature which is in the opposite direction to that, which supply voltage is forcing through the conductor.

So as this e.m.f. always opposes the supply voltage, it is called back e.m.f. and denoted as Eb Though it is denoted as Eb, Basically it gets generated by the generating action which we have seen earlier in case of generators.So its magnitude can be determined by the emf. equation which is derived earlier. So,

Difference Between Shell And Core Type Transformers - Types of Transformers

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In our previous articles we have discusses about differences between lap,wave winding this tutorial we are sharing major differences between core type transformer and shell type transformer. In this tutorial comparisons between shell type and core type transformers are discussed.There are two major types of transformers based on construction.
They are,
1.Core Type Transformers
2.Shell Type Transformers

Types of Transformers

Difference Between Shell And Core Type Transformers

Core Type TransformersShell Type Transformers
1. In core type transformer winding is placed on
two core limbs.
1. In shell type transformer winding is placed on mid arm
of the core.It is installed on mid-limb of the core.
Other limbs will be used as mechanical supporting
2. Core type transformers have only one magnetic flux path.2. Shell type transformers have two magnetic flux path.
3. It has better cooling since more surface is exposed to
atmosphere.
3. Cooling is not effective in shell type when compared
to core type transformer.
4. It is very useful when we need large size low voltage.4. It is very useful when we need small size high voltage.
5. In core type transformer output is less. Because of losses.
So efficiency will be less than shell type transformer.
5. In core type transformer output is high. Because of
less losses.So efficiency will be more.
6. The winding is surrounded considerable part of core.6. Core is surrounded considerable part of winding of
transformer.
7. It has less mechanical protection to coil.7. It has better mechanical protection to coil.
8. Core has two limbs.8. Core has three limbs.
9. This transformer is easy to repair,Easy to maintain.9. This transformer is not easy to repair.We need a
skilled technician to maintain this type of transformer.
10. In this type transformer concentric cylindrical
winding are used
10. In this type transformer sandwiched winding are used.

Tags:
1.difference between core type and shell type transformer pdf
2.difference between core type and shell type transformer ppt
3.difference b/w core type and shell type transformer
4.Types of transformers 

EMF Method or Synchronous Impedance Method | Voltage Regulation of Synchronous Generator [Alternator]

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Voltage Regulation of Synchronous Generator [Alternator] By EMF Method or Synchronous Impedance Method

EMF method: This method is also known as synchronous impedance method.Here the magnetic circuit is assumed to be unsaturated. In this method the MMFs (fluxes) produced by rotor and stator are replaced by their equivalent emf, and hence called emf method.To predetermine the regulation by this method the following information is to be determined.Armature resistance/phase of the alternator, open circuit and short circuit characteristics of the alternator.
Here we discuss Voltage Regulation of Synchronous Generator [Alternator] by EMF Method or Synchronous Impedance Method.this is better method than direct loading but not best methods to find out voltage regulation.

Synchronous Impedance Method:

To perform  voltage regulation by emf method we need to calculate the following data.
1.Armature Resistance per phase [Ra]
2.Open Circuit characteristics which is a graph between open circuit voltage [Vo.c.] and field current.
3.Short circuit characteristics which is a graph between short circuit current [Is.c.] and field current.
Voltage Regulation Synchronous Generator by Synchronous Impedance Method
In Synchronous Impedance Method we need to calculate OC and SC characteristics to find Synchronous Impedance.so..follow these steps to find out OC & SC test values.
Open Circuit Characteristic (O.C.C.):-

The open-circuit characteristic or magnetization curve is really the B-H curve of the complete magnetic circuit of the alternator. Indeed, in large turboalternators, where the air gap is relatively long, the curve shows a gradual bend. It is determined by inserting resistance in the field circuit and measuring corresponding value of terminal voltage and field current. Two voltmeters are connected across the armature terminals. The machine is run at rated speed and field current is increased gradually to If1 till armature voltage reaches rated value or even 25% more than the rated voltage. Figure illustrates a typical circuit for OC test.The major portion of the exciting ampere-turns is required to force the flux across the air gap, the reluctance of which is assumed to be constant. A straight line called the air gap line can therefore be drawn as shown, dividing the excitation for any voltage into two portions,

(a) that required to force the flux across the air gap, and
(b) that required to force it through the remainder of the magnetic circuit.
The shorter the air gap, the steeper is the air gap line.




Procedure to conduct OC test:
(i) Start the prime mover and adjust the speed to the synchronous speed of the alternator.
(ii) Keep the field circuit rheostat in cut in position and switch on DC supply.
(iii) Keep the TPST switch of the stator circuit in open position.
(iv) Vary the field current from minimum in steps and take the readings of field current and
stator terminal voltage, till the voltage read by the voltmeter reaches up to 110% of rated voltage. Reduce the field current and stop the machine.
(v) Plot of terminal voltage/ phase vs field current gives the OC curve.


Short Circuit Characteristic (S.C.C.):-
The short-circuit characteristic, as its name implies, refers to the behaviour of the alternator when its armature is short-circuited. In a single-phase machine the armature terminals are short-circuited through an ammeter, but in a three phase machine all three phases must be short-circuited. An ammeter is connected in series with each armature terminal, the three remaining ammeter terminals being short-circuited. 

The machine is run at rated speed and field current is increased gradually to If2 till armature current reaches rated value. The armature short-circuit current and the field current are found to be proportional to each other over a wide range, as shown in Figure, so that the short circuit characteristic is a straight line. Under short-circuit conditions the armature current is almost 90° out of phase with the voltage, and the armature mmf has a direct demagnetizing action on the field.The resultant ampere − turns inducing the armature emf are, therefore, very small and is equal to the difference between the field and the armature ampere − turns. 

This results in low mmf in the magnetic circuit, which remains in unsaturated condition and hence the small value of induced emf increases linearly with field current. This small induced armature emf is equal to the voltage drop in the winding itself, since the terminal voltage is zero by assumption. It is the voltage required to circulate the short circuit current through the armature windings. The armature resistance is usually small compared with the reactance.



Short-Circuit Ratio:

The short-circuit ratio is defined as the ratio of the field current required to produce rated volts on open circuit to field current required to circulate full-load current with the armature short-circuited.

Short-circuit ratio = If1/If2

Determination of synchronous impedance Zs:

As the terminals of the stator are short circuited in SC test, the short circuit current is circulated against the impedance of the stator called the synchronous impedance. This impedance can be estimated form the oc and sc characteristics.The ratio of open circuit voltage to the short circuit current at a particular field current, or at a field current responsible for circulating the rated current is called the synchronous impedance.

synchronous impedance Zs = (open circuit voltage per phase)/(short circuit current per phase)
for same If
Hence Zs = (Voc) / (Isc)
for same If
From figure synchronous impedance Zs = V/Isc

Armature resistance Ra of the stator can be measured using Voltmeter Ammeter method. Using synchronous impedance and armature resistance synchronous reactance and hence regulation can be calculated as follows using emf method.

Zs =√(Ra)² + (XS)² and Synchronous reactance Xs =  ( Zs)² - (Ra)²

Hence induced emf per phase can be found as 
Eph = √ [ (V cos  Ø+ IRa)²+ (V sin  Ø ± IXS)²]
where
V = phase voltage per phase = Vph ,
I = load current per phase
in the above expression in second term + sign is for lagging power factor and
– sign is for leading power factor.

% Regulation = [(Eph – Vph / Vph )] x 100

where Eph = induced emf /phase, Vph = rated terminal voltage/phase.


Synchronous impedance method is easy but it will not give accurate results. This method gives the value of regulation which is greater (poor) than the actual value and hence this method is called pessimistic method. The complete phasor diagram for the emf method is shown in above figure.


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Hysteresis Motor Construction & Working

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Hysteresis Motor Construction & Working 

Hysteresis Motor:Single-phase cylindrical (non-salient-pole) synchronous-induction or shaded.pole motors are classed as hysteresis motors. A hysteresis motor has neither a salient-pole rotor nor direct excitation. but nevertheless it rotates at synchronous speed. This type of motor runs into synchronism and runs on hysteresis torque.

Hysteresis Motor Construction & Working

Hysteresis-type lamination, shown in figure are usually made of hardened. high retentive steel rather than commercial. law retentivity dynamo steel.

Working of Hysteresis Motor:As a result of a rotating magnetic field produced by phase splitting or a shaded-pole stator. eddy currents are induced in the steel of the rotor which travel across the two bar paths of the rotor as shown in figure A high-retentivity steel produces a high hysteresis lose. and an appreciable amount of energy is consumed from the rotating field in reversing the current direction of the rotor. At the same time the rotor magnetic field set up by the eddy cur- rents causes the rotor to rotate. A high starting torque is produced a: a result of the high resistance (proportional to hysteresis). As the rotor approaches synchronous speed. the frequency of current reversal in the cross-bars decreases, and the rotor becomes permanently magnetized in one direction as a result of the high retentivity of the steel rotor. Consequently the motor continues to rotate at synchronous speed.


An extremely important use of this type of motor is for the rotation of gyroscopc rotors in inertial navigation and control system. Here the requirement is for as near absolute accuracy as can be achieved. One major component of the instrument accuracy that contains the gyroscope is that the gyroscopic moment be absolutely constant. This constancy requires a synchronous motor that is driven by a regulated constant-frequency source.

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Instantaneous Relay Operation

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Instantaneous Relay Working Operation 

What Is Instantaneous Relay ?

An instantaneous relay is one in which there is no time delay provided intentionally. More specifically ideally there is no time required to operate the relay. Although there is some time delay which can not be avoided.

Instantaneous relay. An instantaneous relay is one in which no intentional time delay is provided. In this case, the relay contacts are closed immediately after current in the relay coil exceeds the minimum calibrated value. Figure shows an instantaneous solenoid type of relay. Although there Will be a short time interval between the instant of pickup and the closing of relay contacts, no intentional time delay has been added.

Instantaneous Relay Working Operation


The instantaneous relays have operating time less than 0-1 second. The instantaneous relay is effective only Where the impedance between the relay and source is small compared to the protected section impedance. The operating time of instantaneous relay is sometimes expressed in cycles based on the power-system frequency
e.g. one-cycle would be If 50 second in a 50-cycle system.

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Power Factor | It's Calculation, Power Factor Improvement Methods

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Power Factor | Calculation and Power Factor Improvement Methods


What Is Electrical Power Factor ?

The cosine of angle between voltage and current in an a.c. circuit is known as power factor. In an a.c. circuit, there is generally a phase difference φ between voltage and current. The term cos φ is called the power factor of the circuit. If the circuit is inductive, the current lags behind the voltage and the power factor is referred to as lagging. However, in a capacitive circuit, current leads the voltage and power factor is said to be leading.



Consider an inductive circuit taking a lagging current I from supply voltage V; the angle of lag being φ. The phasor diagram of the circuit is shown in Fig. 6.1. The circuit current I can be resolved into two perpendicular components, namely ;

(a) I cos φ in phase with V
(b) I sin φ 90°  out of phase with V

The component I cos φ is known as active or wattful component, whereas component I sin φ is called the reactive or wattless component. The reactive component is a measure of the power factor. If the reactive component is small, the phase angle φ is small and hence power factor cos φ will be high. Therefore, a circuit having small reactive current (i.e., I sin φ) will have high power factor and vice-versa. It may be noted that value of power factor can never be more than unity.

(i) It is a usual practice to attach the word ‘lagging’ or ‘leading’ with the numerical value of power factor to signify whether the current lags or leads the voltage. Thus if the circuit has a p.f. of 0·5 and the current lags the voltage, we generally write p.f. as 0·5 lagging.

(ii) Sometimes power factor is expressed as a percentage. Thus 0·8 lagging power factor may be expressed as 80% lagging.

Power Triangle 

The analysis of power factor can also be made in terms of power drawn by the a.c. circuit. If each side of the current triangle oab of below figure is multiplied by voltage V, then we get the power triangle OAB shown in figure where
OA = VI cos φ and represents the active power in watts or kW
AB = VI sin φ and represents the reactive power in VAR or kVAR
OB = VI and represents the apparent power in VA or kVA
The following points may be noted form the power triangle :



(i) The apparent power in an a.c. circuit has two components viz., active and reactive power at right angles to each other.
OB² = OA² + AB²
or (apparent power)² = (active power)² + (reactive power)²
or (kVA)²= (kW)² + (kVAR)²

(ii) Power factor, cos φ = OA/OB = active power/apparent power = kW/kVA
Thus the power factor of a circuit may also be defined as the ratio of active power to the apparent power. This is a perfectly general definition and can be applied to all cases, whatever be the waveform.

(iii) The lagging reactive power is responsible for the low power factor. It is clear from the power triangle that smaller the reactive power component, the higher is the power factor of the circuit.
kVAR = kVA sin φ = (kW * sin φ)/cos φ
∴ kVAR = kW tan φ

(iv) For leading currents, the power triangle becomes reversed. This fact provides a key to the power factor improvement. If a device taking leading reactive power (e.g. capacitor) is connected in parallel with the load, then the lagging reactive power of the load will be partly neutralized, thus improving the power factor of the load.

(v) The power factor of a circuit can be defined in one of the following three ways :

(a) Power factor = cos φ = cosine of angle between V and I

(b) Power factor = R/Z= Resistance/Impedance

(c) Power factor = VI/(VI * cosφ) = Active power/Apparent Power

(vi) The reactive power is neither consumed in the circuit nor it does any useful work. It merely flows back and forth in both directions in the circuit. A wattmeter does not measure reactive power.

Disadvantages of Low Power Factor

The power factor plays an importance role in a.c. circuits since power consumed depends upon this
factor.

P = VL IL cos φ

It is clear from above that for fixed power and voltage, the load current is inversely proportional to the power factor. Lower the power factor, higher is the load current and vice-versa. A power factor less than unity results in the following disadvantages :

(i) Large kVA rating of equipment. The electrical machinery (e.g., alternators, transformers, switchgear) is always rated in kVA.
Now, kVA = kW/cos φ
It is clear that kVA rating of the equipment is inversely proportional to power factor. The smaller the power factor, the larger is the kVA rating. Therefore, at low power factor, the kVA rating of the equipment has to be made more, making the equipment larger and expensive.

(ii) Greater conductor size. To transmit or distribute a fixed amount of power at constant voltage, the conductor will have to carry more current at low power factor. This necessitates large conductor size. 

(iii) Large copper losses. The large current at low power factor causes more I²R losses in all the elements of the supply system. This results in poor efficiency.

(iv) Poor voltage regulation. The large current at low lagging power factor causes greater voltage drops in alternators, transformers, transmission lines and distributors. This results in the decreased voltage available at the supply end, thus impairing the performance of utilization devices. In order to keep the receiving end voltage within permissible limits, extra equipment (i.e., voltage regulators) is required.

(v) Reduced handling capacity of system. The lagging power factor reduces the handling capacity of all the elements of the system. It is because the reactive component of current prevents the full utilisation of installed capacity. The above discussion leads to the conclusion that low power factor is an objectionable feature in the supply system.

Causes of Low Power Factor

Low power factor is undesirable from economic point of view. Normally, the power factor of the whole load on the supply system in lower than 0·8. The following are the causes of low power factor:

(i) Most of the a.c. motors are of induction type (1φ and 3φ induction motors) which have low lagging power factor. These motors work at a power factor which is extremely small on light load (0·2 to 0·3) and rises to 0·8 or 0·9 at full load.

(ii) Arc lamps, electric discharge lamps and industrial heating furnaces operate at low lagging power factor.

(iii) The load on the power system is varying ; being high during morning and evening and low at other times. During low load period, supply voltage is increased which increases the magnetization current. This results in the decreased power factor.

Power Factor Improvement Methods 


The low power factor is mainly due to the fact that most of the power loads are inductive and, therefore, take lagging currents. In order to improve the power factor, some device taking leading power should be connected in parallel with the load. One of such devices can be a capacitor. The capacitor draws a leading current and partly or completely neutralists the lagging reactive component of load current. This raises the power factor of the load.

Principles of Power Systems By V.K Mehta PDF Free Download

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Principles of Power Systems By V.K Mehta PDF Free Download

Now you can read & learn electrical power systems in offline.You can download Principles of Power Systems By V.K Mehta. This is a very nice book with attractive colors & amazing images.All concepts of power systems are explained very clearly.You can get idea behind every power concept in single read.You can use principle of power system by vk mehta free download in doc format as text in image can be copied.

We are sharing only the link of this book which is already on internet.We respect copy right policy of principle of power system by vk mehta book publishers.

What You Get In Principles of Power Systems By V.K Mehta 


CONTENTS
Introduction 
Generating stations 
Variable load on power stations 
Economics power generation 
Tariff 
Power factor improvement 
Supply systems 
Mechanical design of overhead lines 
Electrical desing of overhead lines 
Performance of transmission lines 
Underground cables 
Distribution system general 
D.C Distribution 
A.C Distribution 
Voltage control 
Introduction to switchgear 
Symmetrical fault calculations 
Unsymmetrical fault calculations 
Circuit breakers 
Fuses 
Protective relays 
Protection of Alternators and transformers 
Protection of busbars and lines 
Protection againts overvoltages 
Substations 
Neutral Grounding 


Download Here


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Methods To Cool Down A Power Transformer | Cooling Methods Of Transformer

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 Cooling Methods Of Power Transformer 

The transformers get heated due to iron and copper looses occurring in them. It is necessary to dissipate this heat so that the temperature of the windings is kept below the value at which the insulation begins to deteriorate. The cooling of transformer is more difficult than that of rotating machines because the rotating machines create a turbulent airflow which assists in removing the heat generated due to losses. Luckily the losses in transformers are comparatively small. Nevertheless the elaborate cooling arrangements have been devised to deal with the whole range of sizes.

Types of transformer cooling methods:

As far as cooling methods are concerned. the transformers are of following two types

1. Dry type. 2. Oil immersed type.

Dry Type Transformers. Small transformers up to 25 KVA size are of the dry type and have the following cooling arrangements:

(i) Air natural. In this method the natural circulation of surrounding air is utilized to carry away the heat generated by losses. A sheet metal enclosure protects the winding from mechanical injury.

(ii) Air blast. Here the transformer is cooled by a continuous blast of cool air forced through the core and windings . The blast is produced by a fan. The air supply must be filtered to prevent accumulation of dust in ventilating ducts.

Oil Immersed Transformers. In general most transformers are of oil immersed types. The oil provides better insulation than air and it is a better conductor of heat than air. Mineral oil is used for this purpose.Oil immersed transformers are classified as follows:

i) Oil immersed self-cooled transformer. The transformer is immersed in oil and heat generated in cores and windings is passed to oil by conduction. Oil in contact with heated parts rises and its place is taken by cool oil from the bottom. The natural oil transfer: its heat to the tank walls from where heat is taken away by the ambient air. The oil gets cooler and falls to the bottom from where it is dissipated into the surroundings. The tank mince is the best dissipate of heat but a plain tank will have to be excessively large, if used without any auxiliary means for high rating transformers. As both space and oil are costly, these auxiliary means should not increase the cubic capacity of the tank. 
The heat dissipating capacity can be increased by providing (i) corrugations. (ii) fins (iii) tubes and (iv) radiator tanks.


The advantages of ‘oil natural' cooling is that it does not clog the ducts and the windings are fire from effect of moisture.

(ii) Oil immersed forced air-cooled transformers. In this type of cooling, air is directed over the outer surfaces of the tank of the transformer immersed in oil.

(iii) Oil immersed water-cooled transformers. Heat is extracted from the oil by means of a stream of water pumped through a metallic coil immersed in the oil just below the top of the tank.The heated water is in turn cooled in a spray pond or a cooling tower.

(iv) Oil immersed forced oil cooled transformers. In such transformers heat is extracted from the oil by pumping the oil itself upward through the winding and then back by way of external radiators which may themselves be cooled by fans. The extra cost of oil pumping equipment must of course economically justified but it has incidentally the advantage of reducing the temperature difference between top and bottom of enclosing tank. 

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Moving Iron Instrument Working Operation

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Moving Iron Instruments or MI Instruments

In our previous article we have discussed PMMC Instrument Working Opeartion. In this tutorial on Moving Iron Instrument Working Operation we go through the construction & basic principle of MI type instrument.  

The moving iron instruments are classified as:
i) Moving iron attraction type instruments
ii) Moving iron repulsion type instruments

Moving Iron Attraction Type Instrument Working Operation

Moving Iron Instrument Working Principle : The basic working principle of these instruments is very simple that a soft iron piece if brought near magnet gets attracted by the magnet.

The construction of the attraction type moving iron instrument is shown in the below figure.


lt consists of a fixed coil C and moving iron piece D. The oil is flat and has narrow slot like opening. The moving iron is a flat disc which is eccentrically mounted on the spindle. The spindle is supported between the jewel bearings. The spindle carries a pointer which moves over a graduated scale.The number of turns of the fixed coil are dependent on the range of the instrument. For passing large current through the coil only few turns are required.

The controlling torque is provided by the springs but gravity control may also be used for vertically mounted panel type instruments.

The damping torque is provided by the air friction. A light aluminium piston is attached to the moving system. it moves in a fixed chamber. The chamber is closed at one end. it can also be provided with the help of vane attached to the moving system.

The operating magnetic field in moving iron instruments is very weak. Hence eddy current damping is not used since it requires a permanent magnet which would affect or distort the operating field.This is the reason Why why eddy current damping is not used in moving iron instrument.

Moving Iron Repulsion Type Instrument

Moving iron repulsion Type instruments have two vanes inside the coil. the one is fixed and other is movable. When the current flows in the coil, both the vans are magnetized with like polarities induced on the same side. Hence due to the repulsion of like polarities, there is a force of repulsion between the two vanes causing the movement of the moving vane. The repulsion type instruments are the most commonly used instruments.

The two different designs of repulsion type instruments are:
i) Radial vane type and
ii) Co-axial vane type

Radial Vane Emulsion Typo Instrument

Below shows the radial vane repulsion type instrument. Out of the other moving iron mechanisms, this is the moat sensitive and has most linear scale.


The two vanes are radial strips of iron. The fixed vane is attached to the coil. The movable vane is attached to the spindle and suspended in the induction field of the coil. The needle of the instrument is attached to this vane.

Even-though the current through the coil is alternating, there is always repulsion between the like poles of the fixed and the movable vane. Hence the deflection of the pointer is always in the same direction. The deflection is effectively proportional to the actual current and hence the scale is calibrated directly to read amperes or volts. The The calibration is accurate only for the frequency for which it is designed because the impedance is different for different frequencies.

Concentric Vane Repulsion Type Instrument

Figure shows the concentric vane repulsion type instrument. The instrument has two concentric vanes. One is attached to the coil frame rigidly while the other can rotate co-axially inside the stationary vane.



Both the vanes are magnetized to the same polarity due to the current in the coil. Thus the movable vane rotates under the repulsive force. As the movable vane is attached to the pivoted shaft, the repulsion results in a rotation of the shaft. The pointer deflection is proportional to the current in the coil. The concentric vane type instrument is moderately sensitive and the deflection is proportional to the square of the current through coil. Thus the instrument said to have square low response. Thus the scale of the instrument is non-uniform in nature. Thus whatever may be the direction of the current in the coil, the deflection in the moving iron instruments is in the same direction. Hence moving iron instruments can be used for both a.c. and d.c. measurements. Due to square low response, the scale of the moving iron instrument is non-uniform.

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Torque Equation Of Moving Iron Instruments

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In previous tutorial on Moving Iron Instrument Operation construction & working principle was discussed. In this post moving iron instrument torque equation will be derived.


Torque Equation of Moving Iron Instruments


READ HERE Moving Iron Instrument Working Operation CLICK HERE 

Consider a small increment in current supplied to the coil of the instrument. due to this current let dθ be the deflection under the deflecting torque Td. Due to such deflection, some mechanical work will be done.
Mechanical Work = Td .dθ
      
There will be a change in the energy stored i the magnetic field due to the change in inductance. This is because the vane tries to occupy the position of minimum reluctance. The inductance is inversely proportional to the reluctance of  the magnetic circuit of coil.

Let   I = initial current
L = instrument inductance
θ = deflection
dI = increase in current
dθ = change in deflection
dL = change in inductance

In order to effect an increment dL in the current, there must be an increase in the applied voltage given by,

e = d(L*I)/dt
   = I * dL/dt + T * dI/dt     as both I and L are changing.

The electrical energy supplied is given by 

eIdt = { I * dL/dt + T * dI/dt }Idt
       =I²dL + ILdI
The stored energy increases from 1/2*(LI²) to 1/2*[(L+dL)(I+dI)²]
Hence the change in stored energy is given by,
1/2*[(L+dL)(I+dI)²] - 1/2*(LI²)
Neglecting higher order terms,this becomes ILdI +  1/2 * I² dL
The energy supplied in nothing but increase in stored energy plus the energy required for mechanical work done.

I²dL + ILdI = ILdI + 1/2*(I²)dL +Td.
Td.dθ =  1/2( I².dL )

Td = 1/2  I²dL/dθ

While the controlling torque is given by,
Tc = Kθ
where K = spring constant 
Kθ = 1/2  I²dL/dθ
θ = 1/2  I²dL/dθ * 1/K      under equilibrium 






Thus the deflection is proportional to the square of the current through the coil. And the instrument gives square law response.

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